A progression of numbers in which every term bears a constant ratio with the preceeding term is called Geometric progression.
The constant ratio is called the common ratio of the GP
If the first term is a and common ratio is r then,
GP is a,ar,ar2,ar3,…..
Formula:
Tn = arn-1
Sn = (a(1-rn))/(1-r)
Where,
Tn is the nth term in the GP,
Sn is the sum of n terms in the GP,
a is the first term,
r is the common ratio of the GP,
n is the number of term in the GP.
Example1:
Find the 10 th term in the GP 2,4,8,16,….
Solution:
Step1: | ||
Use the formula, Tn = arn-1 | ||
Step2: | ||
In the given problem, | ||
a=first term=2 | ||
r=common ratio=2 | ||
(to find common ratio take any two terms in the GP and find the quotient(4/2=2)) | ||
n=10 | ||
Step3: | ||
Apply values of step 2 in step 1 | ||
T10=2 * 2 9 | ||
=1024 | ||
The 10 th term in the given GP is 1024 |
Find the sum of 5 terms in the GP 2,4,8,16,….
Solution:
Step1: | ||
Use the formula, Sn = (a(1-rn))/(1-r) | ||
Step2: | ||
In the given problem, | ||
a=first term=2 | ||
r=common ratio=2 | ||
(to find common ratio take any two terms in the GP and find the quotient(4/2=2)) | ||
n=5 | ||
Step3: | ||
Apply values of step 2 in step 1 | ||
S5=(2 * (1-25))/(1-2) | ||
=62 | ||
The sum of 5 terms in the given GP is 62 |
Geometric progression(GP)
is explained in this articleFor details regarding Arithmetic Progression click here
Nice to get the explanation for the formulas
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